Given a
pattern and a string str, find if str follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in
pattern and a non-empty word in str.
Examples:
- pattern =
"abba", str ="dog cat cat dog"should return true. - pattern =
"abba", str ="dog cat cat fish"should return false. - pattern =
"aaaa", str ="dog cat cat dog"should return false. - pattern =
"abba", str ="dog dog dog dog"should return false.
Notes:
You may assume
You may assume
pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.
Solution:
There are multiple ways to solve this problem. But the idea is basically the same.
I will post the most concise one that I saw in the discussion section.
public boolean wordPattern(String pattern, String str) {
String[] words=str.split(" ");
HashMap map=new HashMap();
if(words.length!=pattern.length()) return false;
for(Integer i=0;i<words.length;i++){
if(map.put(words[i],i)!=map.put(pattern.charAt(i),i)) return false;
}
return true;
}
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