Write a program to find the nth super ugly number.
Super ugly numbers are positive numbers whose all prime factors are in the given prime list
primes
of size k
. For example, [1, 2, 4, 7, 8, 13, 14, 16, 19, 26, 28, 32]
is the sequence of the first 12 super ugly numbers given primes
= [2, 7, 13, 19]
of size 4.
Note:
(1)
(2) The given numbers in
(3) 0 <
(4) The nth super ugly number is guaranteed to fit in a 32-bit signed integer.
(1)
1
is a super ugly number for any given primes
.(2) The given numbers in
primes
are in ascending order.(3) 0 <
k
≤ 100, 0 < n
≤ 106, 0 < primes[i]
< 1000.(4) The nth super ugly number is guaranteed to fit in a 32-bit signed integer.
Solution:
The idea is exactly the same as ugly number.
Time complxity: O(n*k) k is the length of prime array.
public int nthSuperUglyNumber(int n, int[] primes) {
if(n==1) return 1;
int[] ugly=new int[n];
ugly[0]=1;
int[] index=new int[primes.length];
for(int i=1;i<n;i++){
ugly[i]=Integer.MAX_VALUE;
for(int j=0;j<primes.length;j++){
ugly[i]=Math.min(ugly[i],primes[j]*ugly[index[j]]);
}
if(i==n-1) break;
for(int j=0;j<primes.length;j++){
if(ugly[i]%primes[j]==0) index[j]++;
}
}
return ugly[n-1];
}
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