You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Output: 7 -> 0 -> 8
My solution is straightforward, as long as l1,l2 is not null or carry is non-zero, create a new ListNode by calculating the sum and updating the carry. This method require some attention of processing null-pointer. l1 and l2 are both possibly null when they are iterated.
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
if(l1==null && l2==null) return null;
ListNode predummy=new ListNode(0);
ListNode pre=predummy;
ListNode cur1=l1;
ListNode cur2=l2;
int sum=0;
int carry=0;
while(cur1!=null || cur2!=null || carry!=0){
int num1=(cur1==null)? 0: cur1.val;
int num2=(cur2==null)? 0: cur2.val;
sum=num1+num2+carry;
ListNode temp=new ListNode(sum%10);
pre.next=temp;
pre=pre.next;
carry=sum/10;
if(cur1!=null) cur1=cur1.next;
if(cur2!=null) cur2=cur2.next;
}
return predummy.next;
}
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